Area Calculation - Online Quiz



Following quiz provides Multiple Choice Questions (MCQs) related to Area Calculation. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Questions and Answers

Q 1 - A room is 49/4 m long and 7 m wide. The greatest length of a square tile to fill the floor of the room with entire number of tiles ought to be.

A - 200 cm

B - 175 cm

C - 125 cm

D - 150 cm

Answer : B

Explanation

L=1225 cm and b= 700 cm
Maximum length of the square tile= H.C.F of (1225cm, 700cm) =175 cm

Q 2 - The length of a rectangular plot is thrice its expansiveness. On the off chance that the zone of the rectangular plot is 6075 sq. meter, what is its length?

A - 45 m

B - 75 m

C - 130 m

D - none of these

Answer : D

Explanation

Let the breadth be x meters. Then, its length= 3x mtr.
∴3x*x =6075 ⇒ x2 =2025 ⇒x= √2025= 45
∴ Length = (3*45) m= 135 m

Q 3 - If every side of a square is expanded by half, the proportion of the territory of the subsequent square to the range of the given square is:

A - 5:4

B - 9:4

C - 4:5

D - 4:9

Answer : B

Explanation

Let the original side be x mtr. Then, area =x2 sq. mtr.
New side = (150% of x) m = (150/100* x) m = (3x/2) m
New area = (3x/2*3x/2) m2= 9x2/4 m2
Required ratio of areas = 9x2/4: x2= 9:4

Q 4 - The length and the broadness of a rectangular land parcel are in the proportion of 5:3. The proprietor spent rs. 3000 encompassing it from all sides at Rs. 7.50 for each meter. The distinction between its length and broadness is:

A - 50 m

B - 100 m

C - 150 m

D - 200 m

Answer : A

Explanation

Let length = 5x meters and breadth = 3x meters.
Then, perimeter= 2(5x+3x) m = 16x m.
But, perimeter = 3000/7.50m = (3000*2/15) m = 400m
∴ 16x =400 ⇒ x=25
∴ L= 125 m and b= 75 m
(L-b)= (125-75) m = 50 m

Q 5 - The perimeter of a square circumscribed about a circle of radius r is:

A - 2r

B - 4r

C - 8r

D - 21πr

Answer : C

Explanation

Each side of the square = 2r
∴ Perimeter of the square = (4* 2r) = 8r.

Q 6 - The ratio of the area of a square of side a and that of an equilateral triangle of side a, is

A - 2:1

B - 2:√3

C - 4:3

D - 4:√3

Answer : D

Explanation

Required ratio  = a2/(√3/4) a2  = 4/√3=  4:√3

Q 7 - The perimeter of a square and that of an equilateral triangle are equal. If the length of diagonal of the square be 12 √2cm, then area of the triangle is:

A - 64√3 cm2

B - 32√3 cm2

C - 24√3 cm2

D - 24√2 cm2

Answer : A

Explanation

Let each side of the square be a cm.
Then, its diagonal= √2A cm.
∴ √2 A= 12 √2 ⇒ A = 12.
Perimeter of the triangle= Perimeter of the square = (12*4) =48 cm
Each side of the triangle =48/3= 16 cm
Area of the triangle = (√3/4* 16*16) cm2= 64√3 cm2

Q 8 - The edges of a square and a rectangle are equivalent. On the off chance that their zones are individually A m and B m, then which of the accompanying is a genuine proclamation.

A - A < B

B - A≤B

C - A > B

D - A≥B

Answer : C

Explanation

If the perimeter of a square  and a rectangle are equal, then area of the square is more. So, A>B is true.

Q 9 - If the side of a rhombus is 20cm and its shorter corner to corner is three-fourth of its more extended askew, then the range of the rhombus is:

A - 375 cm2

B - 380 cm2

C - 384 cm2

D - 395 cm2

Answer : C

Explanation

Let the longer diagonal be x cm , then shorter diagonal = (3/4)x cm
∴ AC= x cm and BD=(3/4 )x cm
AO =1/2*AC =x/2 cm, BO= 1/2 BD= (3/8) X cm and AB= 20 cm
In right ∆ AOB, we have AO2 +BO2 = AB2
(x/2) 2+ (3x/8) 2= (20) 2⇒x2/4+9x2/64=400 ⇒16x2+9x2=25600 ⇒25x2= 25600 ⇒x2=1024
⇒ x=√1024= 32 cm
∴ AO =32/2=16cm, BO= (3/8*32) cm=12cm
∴ AC=2*AO= 32 cm, BD= 2*BO= 24cm
Area of the rhombus = (1/2*32*24) cm2 =384 cm2

Q 10 - The edge of a circle and a square field are equivalent. What is the Breadth of the round field, if the region of the square field is484m2?

A - 14 m

B - 21 m

C - 28 m

D - none of these

Answer : C

Explanation

Let the side of the square be a meters. Then,
a2= 484 ⇒a =√484 =22m
Perimeter of circle =Perimeter of the square= (22*4) m = 88m
⇒2* 22/7*R = 88 ⇒R= (88*7/44) = 14m
∴ Diameter= (14*2) m = 28m

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