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Aptitude - Ratios Online Quiz

Following quiz provides Multiple Choice Questions (MCQs) related to Ratios. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Q 1 - If three numbers are in the ratio 3:7:11 and double the sum is 84, then the ratio of squares of the numbers is

Answer : B

Explanation

Let the numbers are 3x:7x:11x
It is given that 2(3x+7x+11x) = 84
 => x=2
Ratio 6:14:22 or 3:7:11
 Their squares 9:49:121

Q 2 - If 19 inches correspond to 48.26 cm, how many numbers of Centimeters are there in 39 inches?

Answer : B

Explanation

Let 39 inches corresponds to x cm.
Given that 19 inches corresponds to 48.26 cm
=>19/48.26=39/x
=>x=39/19*48.26=99.06

Q 3 - If a:b =3:4 and b:c =8:9 , then a:c =?

Answer : D

Explanation

a/b = (a/b * b/c) = (3/8 *8/9 ) = 2/3 
Consequently a :c =2:3.

Q 4 - If x:y =3:4 ,then (7x+ 3y): (7x-3y)=?

Answer : C

Explanation

Now x/y =3/4
(7x+3y)/(7x-3y)  = (7 * x/y + 3)/(7 * x/y -3)
= (7 *3/4 +3)/(7* 3/4  - 3 ) 
= (21+12)/(21-12) = 33/9 =11/3
∴  (7x+3y) : (7x-3y)= 11:3

Q 5 - The proportion between two no. is 3:4 . on the off chance that every no. is expanded by 6, the proportion gets to be 4:5 . The no's distinction. is ?

Answer : C

Explanation

Let the numbers be 3x and 4x.  At that point,
3x+6/4x+6 = 4/5 => 5 (3x+6) =4 (4x+6) => x=(30-24) =6 
Contrast between the numbers = (4x-3x) = x = 6.

Q 6 - Instead of partitioning rs. 117 among P, Q, R in the proportion 1/2: 1/3:1/4, by misstep it was isolated in the proportion 2:3:4 . who picked up in the exchange?

Answer : D

Explanation

P = Rs(117*6/13)= Rs 54,
Q = Rs(117*4/13)= Rs 36 
And R = Rs(117*3/13)=Rs 27.
 Again, the ratio is 2:3:4.  
 P =Rs(117*2/9)= Rs 26,
Q= Rs (117*3/9)=Rs 39 
And R=RS(117*4/9)=Rs 52.
 Thus, both Q and R gained in the transaction.

Q 7 - At the point when 20% of a no. is added to another no., the no. increment by half. What is the proportion between the first and the second no?

A - 3:2

B - 2:3

C - 5:2

D - cannot be resolved

Answer : C

Explanation

Let the numbers be x and y. Then,
Y+ 20x/100 = (150/100)y
=> x/5 ={ (3/2)y-y}= y/2
=> 2x-5y
=> x/y=5/2 
=> x:y =5:2

Q 8 - Three numbers A , B and C are in the proportion 1:2 :3. Their normal is 600. In the event that An is expanded by 10% and B is diminished by 20 %, then to get the normal expanded by 5%, C will be expanded by:

Answer : D

Explanation

Let A= x, B= 2x and C=3x, then,
      (X+2x+3x)/3 =600 
=> 6x =1800 
=>x= 300
  ∴  the numbers are 300, 600, 900.
  New average= 105% of 600 =(105/100*600)= 630.
    Let 110% of 300+ 80% of 600 +y=630*3
     => (110/100*300) +(80/100*600)+y =1890
=> (330+480)+y= 1890 
=> y=1890-810 =1080
     Increase in C= (1080-900) =180.

Q 9 - Rs. 1050 is partitioned among p, q and r in a manner that the offer of p is 2/5 of the consolidated offer of q and r. Therefore p gets:

Answer : B

Explanation

Given: P=2/5 (Q+R) 
=> P :( Q+R)= 2:5
∴ P share =(1050*2/7)= 300.

Q 10 - A and B are two compounds of gold and copper arranged by blending metals in the extent 7:2 and 7:11 separately. In the event that the equivalent amounts of the combination are dissolved to frame a third amalgam C, the extent of gold and copper In C will be:

Answer : C

Explanation

Gold in C=(7/9+7/18)=21/18=7/6.
Copper in C=(2/9+11/18)=15/18=5/6.
∴Gold:Copper=7/6:5/6=7:5.

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