Simplification - Online Quiz



Following quiz provides Multiple Choice Questions (MCQs) related to Simplification. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Questions and Answers

Q 1 - 254* ? * 8 = 95504

A - 47

B - 49

C - 51

D - 53

Answer : A

Explanation

let 254 * x * 8= 95504. Than , x = 95504/ 254 * 8 = 47.

Q 2 - 7+ 7 + 7/7/(7 + 7 +7) / 7 = ?

A - 15/21

B - 5

C - 125/3

D - 46/3

Answer : B

Explanation

given exp = 7+7+1/(21/7)  = 15/3 = 5 

Q 3 - 998996/999 * 999 = ?

A - 990809

B - 998996

C - 998999

D - 999824

Answer : B

Explanation

given exp= (1000-4/ 999)*999 = (999000-4 )= 998996

Q 4 - 1/ 1*2*3 + 1/ 2*3*4 +1/ 3*4*5 + 1/ 4*5*6 =?

A - 1/30

B - 7/30

C - 11/30

D - 13/30

Answer : B

Explanation

given exp .  =  (4*5*6+5*6+12+6)/(1*2*3*4*5*6) = (120+30+12+6)/(1*2*3*4*5*6)
=168/(2*3*4*5*6) =  7/30

Q 5 - If 1/ 1+ 1 / 1+ 1/x = 2 then x = ?

A - ? 1/3

B - ? 1

C - 1/3

D - 1

Answer : A

Explanation

1/(1+ 1/ (1+1/x)) = 2
⇒ 1/(1+x/(x+1)) = 2
⇒ (x+1)/ (2x+1) = 2
⇒ x+1= 4x+2
⇒ 3x= -1
⇒ x= -1/3

Q 6 - (1-1/2) (1-1/3) (1-1/4) ... (1- 1/n) = ?

A - 1/n

B - 1/(n-1)

C - n/(n-1)

D - none of these

Answer : A

Explanation

given exp.  = (1- 1/2) (1-1/3 ) ( 1- 1/4) ...{1-    1/(n-1)}(1- 1/n)
= 1/2 * 2/3 *3/4 *...*(n-2)/(n-1)* (n-1)/n = 1/n

Q 7 - if (a+2b) =6 and ab = 4 , then (2/a+1/b) = ?

A - 1/2

B - 1/3

C - 3/2

D - 2

Answer : C

Explanation

(2/a + 1/b) = (a +2b)/ab = 6/ 4 = 3/2.

Q 8 - if a+b = 5 and 3a +2b = 20, then (3a+b) = ?

A - 10

B - 15

C - 20

D - 25

Answer : D

Explanation

on solving a+b = 5 and 3a+ 2b = 20 , we get a =10 ,b = -5
∴ (3a+b) = (3*10-5) = 25

Q 9 - ((856+167)2 +(856-167)2)/(856*856+ 167*167)= ?

A - 1

B - 2

C - 689

D - 1023

Answer : B

Explanation

given exp.  = (a+b)2 +(a-b)2/ (a2+b2),   where a = 856 , b = 167
= 2 (a2+b2) /(a2+b2) = 2

Q 10 - 1/4th of Naresh money is equal to 1/6th of Suresh money. If the joint amount of Naresh and Suresh is Rs. 600 then what should be the differences between both amounts?

A - 80

B - 100

C - 120

D - 140

Answer : C

Explanation

1/4 *x = 1/6 *y = h . then , x= 4h and y = 6h
4h+6h = 600 ⇒ 10h= 600 ⇒ h = 60.
Required difference =  Rs. (6h-4h) = 2h = Rs.  (2*60) = Rs.120.

aptitude_simplification.htm
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