Volume Calculation - Online Quiz



Following quiz provides Multiple Choice Questions (MCQs) related to Volume Calculation. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Questions and Answers

Q 1 - The region of the base of a rectangular tank is 6500 cm2 and the volume of the water contained in it in 2.6 cubic meter. The profundity of the water in the tank is:

A - 2.5 m

B - 3 m

C - 5.5 m

D - 4 m

Answer : D

Explanation

L*b= 6500cm2 , L*b*d=2.6m3=(2.6*100*100*100) cm3
∴ d = (2.6*100*100*100)/6500 cm = (2.6*100*100*100)/6500*100 = 4m
∴ Depth = 4m

Q 2 - Half cubic meter of gold sheet is stretched out by pounding in order to spread a region of 1 hectare. The thickness of the sheet is:

A - 0.5 cm

B - 0.05 cm

C - 0.005 cm

D - 0.0005 cm

Answer : C

Explanation

Area = 1 hectare= 10000m2, Volume = 0.5 m3
Thickness =Volume/Area   = (0.5/10000)m =(0.5*100/10000)cm=0.005cm

Q 3 - A swimming shower is 24 m long and 15 m wide. At the point when various men jump into the shower, the tallness of water ascends by 1 cm. On the off chance that the normal volume of water uprooted by every men be 0.1 m3, what number of men arrive in the shower?

A - 32

B - 36

C - 42

D - 46

Answer : B

Explanation

Let there be x man in the bath .Then,
x *0.1= (24*15*1/100) ⇒x*1/10=   24*15*1/100⇒x= 36.

Q 4 - A room is 10 m long, 8m wide and 3.3 m high. What number of men can be obliged in this room if every man requires 3m3 of space?

A - 99

B - 88

C - 77

D - 75

Answer : B

Explanation

Volume of the room = (10*8*3.3) m3= 264m3
Volume required by 1man = 3m3
Required number of men = 264/3 = 88

Q 5 - If every side of a solid shape is multiplied, then its volume:

A - is multiplied

B - get to be 4 times

C - gets to be 6 times

D - Gets to be 8 times

Answer : D

Explanation

Let the edge of the original cube be x. Then its volume = x3
New edge = 2x, new volume (2x) 3=8x3
So, it?s become 8 times.

Q 6 - The volume of a cuboid is twice that of a solid shape. On the off chance that the measurement of the cuboid is (9cm *8 cm* 6cm), the aggregate surface region of the block is:

A - 72 cm2

B - 216 cm2

C - 108 cm2

D - 432 cm2

Answer : B

Explanation

2*volume of cube= volume of cuboid= (9*8*6) cm3
Volume of cube = (1/2 *9*8*6) cm3= 216cm3
∴ a3= 216 = (6) 3 ⇒a =6 cm
Total surface area = 6a2 = (6*6*6) cm2= 216cm2

Q 7 - How numerous 3D squares of 10 cm edge can be placed in a cubic box of 1 m edge?

A - 10

B - 100

C - 1000

D - 10000

Answer : C

Explanation

Required no. = (100*100*100)/ (10*10*10) = 1000

Q 8 - Water streams out through a round funnel whose inner measurement is 2cm, at the rate of 6 meters for each second into a barrel shaped tank, the range of whose base is 60 cm. By what amount will the level of water ascend in 30 minutes?

A - 2 m

B - 3 m

C - 4 m

D - 5 m

Answer : B

Explanation

Length flown in 30 minutes = (6*60*30) m =   10800 m
r = 1/100m, h = 10800 m
Volume = (π*1/100*1/100*10800) m3
Let the height of the water level be h meters. Then,
π*60/100*60/100*h = π*1/100*1/100*10800
⇒ h = (108/100*5/3*5/3) = 3m

Q 9 - The range and the base and stature of a barrel are in the proportion 2:3 and its volume is 12936 cm3. The entire surface territory of the barrel is:

A - 3080 cm2

B - 38808 cm2

C - 25872 cm2

D - 2587.2 cm2

Answer : A

Explanation

Let radius =2x cm and height= 3x cm
Then volume = πr2h [22/7(2x) 2*3x] cm3= (264/7) x3 cm3
(264/7) x3= 12936 ⇒x3= (12936*7/264) =343= (7)3⇒x= 7
∴ Radius =14cm, height = 21 cm
Total surface area = 2πr (h+r) = [2*22/7*14(21+14)] cm2= 3080 cm2

Q 10 - The volume of a circle is 4851 cm3. Its bended surface range is:

A - 1716 cm2

B - 1386 cm2

C - 1625 cm2

D - 3087 cm2

Answer : B

Explanation

4/3πr3= 4851 ⇒ 4/3*22/7*r 3= 4851
⇒r3 = (4851*21/88) = (441*21)/8 = (21/2)3 ⇒r = 21/2
Curved surface area = 4πr2= (4*22/7*21/2*21/2) cm2=1386 cm2

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